Let the 5 numbers be = a, b, c and d
(1) The 1st digit is half of the second
a = b/2____________(1)
(2) The sum of the 2nd and 3rd is 10
b + c = 10
∴ b =10 - c__________(2)
(3) The 4th is equal to the 2nd plus 1
d = b + 1_______(3)
(4)The sum of all the digits is 23
a + b + c + d = 23________(4)
Now, let solve the equations:
Note: a = b/2, b= 10 - c, d = b + 1,
Now, substitute those values in: a + b + c + d = 23
b/2 + 10-c + c + b +1=23
b/2 + 10 + b =22
b + 20 + 2b = 44
3b = 24
b=8
Substitute b=8 in equation(1)
a = b/2
a =8/2
a=4
Substitute b=8 in equation (2)
b =10-c
8= 10 -c
c=2
Substitute b=8 in equation (3)
d = b +1
d = 8 +1
d =9
Hence, abcd=4829
Therefore, the five numbers is: 4829
DONE !
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